The Delta method is a theorem that can be used to derive the distribution of a function of an asymptotically normal variable.
It is often used to derive standard errors and confidence intervals for functions of parameters whose estimators are asymptotically normal.
Let
be a sequence of random variables such
that
where:
is a normal distribution with
mean
and variance
;
is a constant;
indicates convergence in distribution.
is said to be asymptotically normal,
is called the asymptotic mean of
and
its asymptotic variance.
For example,
could be a sequence of sample means
that are asymptotically normal because a
Central Limit Theorem applies. Or it
could be a sequence of maximum
likelihood estimators satisfying a set of conditions that are sufficient
for asymptotic normality.
Now, consider the sequence
where
is a function.
The delta method is a method that allows us to derive, under appropriate
conditions, the asymptotic distribution of
from the asymptotic distribution of
.
A formal statement of the delta method is given in the following proposition.
Proposition
Let
be a sequence of random variables such
that
Let
be a continuously differentiable function. Then,
By the
mean value
theorem, there exists a point
lying between
and
,
such
that
By
subtracting
from both sides and multiplying by
,
we
obtain
Since
converges in probability to
,
and
lies between
and
,
also
converges in probability to
.
Because the derivative
is continuous, by the
continuous mapping
theorem
where
denotes convergence in probability. Therefore, the first term of the product
converges
in probability to a constant. By assumption, the second term converges in
distribution to a normal random variable
having mean
and variance
.
As a consequence, Slutsky's
theorem applies and the product converges in distribution
to
By
elementary rules on
linear transformations
of normal random variables, this has a normal distribution with mean
and
variance
In this example we show how the delta method can be applied.
Suppose that a sequence
is asymptotically normal with asymptotic mean
and asymptotic variance
,
that
is,
We want to derive the asymptotic distribution of the sequence
.
The
functionis
continuously differentiable, so we can apply the delta method.
The asymptotic mean of the transformed sequence
is
In order to compute the asymptotic variance, we need to take the first
derivative of the function
,
which
is
and
evaluate it at
:
Therefore, the asymptotic variance
isand
we can
write
The delta method generalizes also to multivariate settings, as stated by the following proposition.
Proposition
Let
be a sequence of
random vectors such
that
where
is a multivariate normal distribution with mean
and covariance matrix
,
is a constant
vector, and
indicates convergence in distribution. Let
.
If all the
entries of
have continuous partial derivatives with respect to
,
then
where
is the Jacobian of
,
i.e., the
matrix of partial derivatives of the entries of
with respect to the entries of
.
The next example shows how the multivariate delta method can be applied.
Example
Suppose that a sequence of
random vectors
satisfies
where
the asymptotic mean
is
and
the asymptotic covariance matrix
is
Denote
the two components of
by
and
.
We want to derive the asymptotic distribution of the sequence
.
The
function
is
continuously differentiable, so we can apply the delta method. The asymptotic
mean of the transformed sequence
is
In
order to compute the asymptotic covariance matrix, we need to compute the
Jacobian of the function
,
which
is
and
evaluate it at
:
Therefore,
the asymptotic variance
is
and
we can
write
Below you can find some exercises with explained solutions.
Let
be an asymptotically normal sequence with asymptotic mean
and asymptotic variance
,
that
is,
Derive the asymptotic distribution of the sequence
.
The
functionis
continuously differentiable, so we can apply the delta method. The asymptotic
mean of the transformed sequence
is
In
order to compute the asymptotic variance, we need to take the first derivative
of the function
,
which
is
and
evaluate it at
:
Therefore,
the asymptotic variance
is
and
we can
write
Let
be a sequence of
random vectors
satisfying
where
the asymptotic mean
is
and
the asymptotic covariance matrix
is
Denote the two entries of
by
and
.
Derive the asymptotic distribution of the sequence of products
We can apply the delta method because the
functionis
continuously differentiable. The asymptotic mean of the transformed sequence
is
The
Jacobian of the function
is
By
evaluating it
at
we
obtain
Therefore,
the asymptotic covariance matrix
is
and
we can
write
Let
be a sequence of
random vectors
satisfying
where
the asymptotic mean
is
and
the asymptotic covariance matrix
is
Denote the two entries of
by
and
.
Derive the asymptotic distribution of the sequence of
vectors
where the two entries of
satisfy
We can apply the delta method because the
functionsare
continuously differentiable. The asymptotic mean of the transformed sequence
is a
vector
whose entries are
The
Jacobian of the function
is
By
evaluating it
at
we
obtain
As
a consequence, the asymptotic covariance matrix
is
Thus,
where
and
have been calculated above.
Please cite as:
Taboga, Marco (2021). "Delta method", Lectures on probability theory and mathematical statistics. Kindle Direct Publishing. Online appendix. https://www.statlect.com/asymptotic-theory/delta-method.
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