This lecture discusses two properties characterizing probability density functions (pdfs).
Not only any pdf satisfies these two properties, but also any function that satisfies them is a legitimate pdf.
Therefore, in order to determine whether a function is a valid pdf, we just need to verify that the two properties hold.
The following proposition formally describes the two properties.
Proposition
Let
be a continuous
random variable. Its
probability density
function, denoted by
,
satisfies the following two properties:
Non-negativity:
for any
;
Integral over
equals
:
.
Remember that, by the definition of a pdf,
is such
that
for
any interval
.
Probabilities cannot be negative, therefore
and
for
any interval
.
But the above integral can be non-negative for all intervals
only if the integrand function itself is non-negative, that is, if
for all
.
This proves property 1 above (non-negativity).
Furthermore, the probability of a sure thing must be equal to
.
Since
is a sure thing,
then
which
proves property 2 above (integral over
equals
).
Any pdf must satisfy property 1 and 2 above. It can be demonstrated that also the converse holds: any function enjoying these properties is a pdf.
Proposition
Let
be a function satisfying the following two properties:
Non-negativity:
for any
;
Integral over
equals
:
.
Then, there exists a continuous random variable
whose pdf is
.
The practical implication is that we only need to verify that these two properties hold when we want to prove that a function is a valid pdf.
The proposition above also gives us a powerful method for constructing probability density functions.
Take any non-negative function
(non-negative means that
for any
).
If the
integralexists
and is finite and strictly positive, then
define
Since
is strictly positive,
is non-negative and it satisfies Property 1.
The function
also satisfies Property 2
because
Thus, any non-negative function
can be used to build a pdf if its integral over
exists and is finite and strictly positive.
Example
Define a function
as
follows:
How
do we construct a pdf from
?
First, we need to verify that
is non-negative. But this is true because
is always non-negative. Then, we need to check that the integral of
over
exists and is finite and strictly
positive:
Having
verified that
exists and is finite and strictly positive, we can
define
By
the above proposition,
is a legitimate pdf.
Below you can find some exercises with explained solutions.
Consider the following
function:
where
.
Prove that
is a legitimate probability density function.
Since
and the exponential function is strictly positive,
for any
,
so the non-negativity property is satisfied. The integral property is also
satisfied
because
Define the
function
where
and
.
Prove that
is a valid probability density function.
implies
,
so
for any
and the non-negativity property is satisfied. The integral property is also
satisfied
because
Consider the
functionwhere
and
is the Gamma function.
Determine whether
is a valid probability density function.
Remember the definition of Gamma
function:
is obviously strictly positive for any
,
since
is strictly positive and
is strictly positive on the interval of integration (except at
where it is
).
Therefore,
satisfies the non-negativity property because the four factors in the
product
are
all non-negative on the interval
.
The integral property is also satisfied
because
Please cite as:
Taboga, Marco (2021). "Legitimate probability density functions", Lectures on probability theory and mathematical statistics. Kindle Direct Publishing. Online appendix. https://www.statlect.com/fundamentals-of-probability/legitimate-probability-density-functions.
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